Magnetic Effects Of Current Question 25
Question: A charge q coulomb moves in a circle at n revolutions per second and the radius of the circle is r metre. Then magnetic field at the centre of the circle is
Options:
A) $ \frac{2\pi q}{nr}\times {{10}^{-7}} $ N/amp/metre
B) $ \frac{2\pi q}{r}\times {{10}^{-7}} $ N/amp/metre
C) $ \frac{2\pi nq}{r}\times {{10}^{-7}} $ N/amp/metre
D) $ \frac{2\pi q}{r} $ N/amp/metre
Show Answer
Answer:
Correct Answer: C
Solution:
The magnetic field at the centre of the circle $ =\frac{{\mu_{o}}}{4\pi }\times \frac{2\pi i}{r}={{10}^{-7}}\times \frac{2\pi (nq)}{r}=\frac{2\pi nq}{r}\times {{10}^{-7}}N/A\text{-}m $
BETA
