Magnetic Effects Of Current Question 256
Question: A beam of ions with velocity $ 2\times 10^{5},m/s $ enters normally into a uniform magnetic field of $ 4\times {{10}^{-2}},tesla $ . If the specific charge of the ion is $ 5\times 10^{7},C/kg $ , then the radius of the circular path described will be [NCERT 1983; BVP 2003]
Options:
A) 0.10 m
B) 0.16 m
C) 0.20 m
D) 0.25 m
Show Answer
Answer:
Correct Answer: A
Solution:
$ r=\frac{mv}{Bq} $ $ =\frac{v}{(q/m)B}=\frac{2\times 10^{5}}{5\times 10^{7}\times 4\times {{10}^{-2}}}=0.1m $
BETA
