Magnetic Effects Of Current Question 262
Question: A 2 MeV proton is moving perpendicular to a uniform magnetic field of 2.5 tesla. The force on the proton is [CPMT 1989]
Options:
A) $ 2.5\times {{10}^{-10}},N $
B) $ 7.6\times {{10}^{-11}},N $
C) $ 2.5\times {{10}^{-11}},N $
D) $ 7.6\times {{10}^{-12}},N $
Show Answer
Answer:
Correct Answer: D
Solution:
$ F=qvB=1.6\times {{10}^{-19}}\times [ \sqrt{\frac{2E}{m}} ]\ 2.5 $ $ =4\times {{10}^{-19}}\sqrt{\frac{2\times 2\times 1.6\times {{10}^{-19}}\times 10^{6}}{1.66\times {{10}^{-27}}}} $ $ =7.6\times {{10}^{-12}}N $
BETA
