Magnetic Effects Of Current Question 284
Question: A proton and a deutron both having the same kinetic energy, enter perpendicularly into a uniform magnetic field B. For motion of proton and deutron on circular path of radius $ R_{p} $ and $ R_{d} $ respectively, the correct statement is [MP PET 1995]
Options:
A) $ R_{d}=\sqrt{2},R_{p} $
B) $ R_{d}=R_{p}/\sqrt{2} $
C) $ R_{d}=R_{p} $
D) $ R_{d}=2R_{p} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{mv^{2}}{R}=qvB $ . For proton $ R_{p}=\frac{mv}{qB}=\frac{\sqrt{2m_{p}E}}{qB} $ and for deutron $ R_{d}=\frac{\sqrt{2m_{d}E}}{qB} $
$ \Rightarrow ,\ \frac{R_{d}}{R_{p}}=\sqrt{\frac{m_{d}}{m_{p}}}=\sqrt{2}\Rightarrow R_{d}=\sqrt{2}R_{p} $
BETA
