Magnetic Effects Of Current Question 295
Question: An electron is accelerated by a potential difference of 12000 volts. It then enters a uniform magnetic field of $ {{10}^{-3}},T $ applied perpendicular to the path of electron. Find the radius of path. Given mass of electron $ =9\times {{10}^{-31}},kg $ and charge on electron $ =1.6\times {{10}^{-19}},C $ [MP PET 1997]
Options:
A) 36.7 m
B) 36.7 cm
C) 3.67 m
D) 3.67 cm
Show Answer
Answer:
Correct Answer: B
Solution:
$ r=\frac{\sqrt{2mK}}{qB}=\frac{1}{B}\sqrt{\frac{2mV}{q}} $ $ =\frac{1}{{{10}^{-3}}}\sqrt{\frac{2\times 9\times {{10}^{-31}}\times 12000}{1.6\times {{10}^{-19}}}} $ =0.367 m = 36.7 cm
BETA
