Magnetic Effects Of Current Question 316
Question: One proton beam enters a magnetic field of $ {{10}^{-4}} $ T normally, Specific charge = $ 10^{11},C/kg. $ velocity = $ 10^{7},m/s $ . What is the radius of the circle described by it [DCE 1999]
Options:
A) 0.1 m
B) 1 m
C) 10 m
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ r=\frac{mv}{qB}=\frac{10^{7}}{10^{11}\times {{10}^{-4}}}=1m\ (\because \ q/m=10^{11}C/kg) $
BETA
