Magnetic Effects Of Current Question 321
Question: Maximum kinetic energy of the positive ion in the cyclotron is [Pb. PMT 2000]
Options:
A) $ \frac{q^{2}Br_{0}}{2m} $
B) $ \frac{qB^{2}r_{o}}{2m} $
C) $ \frac{q^{2}B^{2}r_{0}^{2}}{2m} $
D) $ \frac{qBr_{0}}{2m^{2}} $
Show Answer
Answer:
Correct Answer: C
Solution:
$ {K_{\max }}=\frac{1}{2}mv^{2} $ and $ r_{0}=\frac{mv}{qB} $
Þ $ v=\frac{qBr_{0}}{m} $
Þ $ {K_{\max }}=\frac{1}{2}m{{( \frac{qBr_{0}}{m} )}^{2}}=\frac{q^{2}B^{2}r_{0}^{2}}{2m} $
BETA
