Magnetic Effects Of Current Question 333
Question: A particle of mass 0.6 g and having charge of 25 nC is moving horizontally with a uniform velocity $ \text{1}\text{.2}\times \text{1}{{\text{0}}^{\text{4}}}m{{s}^{-1}} $ in a uniform magnetic field, then the value of the magnetic induction is $ (g=10,m{{s}^{-2}}) $ [EAMCET 2001]
Options:
A) Zero
B) 10 T
C) 20 T
D) 200 T
Show Answer
Answer:
Correct Answer: C
Solution:
Particle will move with uniform velocity when it?s acceleration is zero. i.e. $ |F_{m}|,=,mg\Rightarrow mg=qvB $
$ \Rightarrow B=\frac{mg}{qv}=\frac{0.6\times {{10}^{-3}}\times 10}{25\times {{10}^{-9}}\times 1.2\times 10^{4}}=20,T $
BETA
