Magnetic Effects Of Current Question 339
Question: Mixed $ H{{e}^{+}} $ and $ {{O}^{2+}} $ ions (mass of $ H{{e}^{+}}=4amu $ and that of $ {{O}^{2+}}=16amu) $ beam passes a region of constant perpendicular magnetic field. If kinetic energy of all the ions is same then [Orissa JEE 2002]
Options:
A) $ H{{e}^{+}} $ ions will be deflected more than those of $ {{O}^{2+}} $
B) $ H{{e}^{+}} $ ions will be deflected less than those of $ {{O}^{2+}} $
C) All the ions will be deflected equally
D) No ions will be deflected
Show Answer
Answer:
Correct Answer: C
Solution:
$ r=\frac{\sqrt{2mK}}{qB}\Rightarrow r\ \propto \ \frac{\sqrt{m}}{q}\Rightarrow \frac{{r_{H{{e}^{+}}}}}{{r_{{{O}^{++}}}}}=\sqrt{\frac{{m_{H{{e}^{+}}}}}{{m_{{{O}^{++}}}}}}\times \frac{{q_{{{O}^{++}}}}}{{q_{H{{e}^{+}}}}} $ $ =\sqrt{\frac{4}{16}}\times \frac{2}{1}=\frac{1}{1}. $ Then will deflect equally.
BETA
