Magnetic Effects Of Current Question 344

Question: A particle of charge $ -16\times {{10}^{-18}} $ coulomb moving with velocity $ 10m{{s}^{-1}} $ along the x-axis enters a region where a magnetic field of induction B is along the y-axis, and an electric field of magnitude $ 10^{4}V/m $ is along the negative z-axis. If the charged particle continues moving along the x-axis, the magnitude of B is [AIEEE 2003]

Options:

A) $ {{10}^{-3}}Wb/m^{2} $

B) $ 10^{3}Wb/m^{2} $

C) $ 10^{5}Wb/m^{2} $

D) $ 10^{16}Wb/m^{2} $

Show Answer

Answer:

Correct Answer: B

Solution:

Since particle is moving undeflected. So $ qE=qvB\Rightarrow B=E/v=\frac{10^{4}}{10}=10^{3}Wb/m^{2} $



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