Magnetic Effects Of Current Question 393
Question: A charged particle of mass m and charge q travels on a circular path of radius r that is perpendicular to a magnetic field B. The time taken by the particle to complete one revolution is
Options:
A) $ \frac{2\pi q^{2}B}{m} $
B) $ \frac{2\pi mq}{B} $
C) $ \frac{2\pi m}{qB} $
D) $ \frac{2\pi qB}{m} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Equating magnetic force to centripetal force, [a] $ \frac{mv^{2}}{r}=qvB,\sin ,90^{o} $ Time to complete one revolution, $ T=\frac{2\pi r}{v}=\frac{2\pi m}{qB} $
BETA
