Magnetic Effects Of Current Question 404

Question: Two particles X and Y having equal charges, after being accelerated through the same potential difference, enter a region of uniform magnetic field and describe circular paths of radii $ R_{1} $ and $ R_{2} $ respectively. The ratio of the mass of X to that of Y is

Options:

A) $ {{(R_{1}/R_{2})}^{1/2}} $

B) $ R_{2}/R_{1} $

C) $ {{(R_{1}/R_{2})}^{2}} $

D) $ R_{1}/R_{2} $

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Answer:

Correct Answer: C

Solution:

[c] K.E. of first particle $ =\frac{1}{2}m_{1}v_{1}^{2}=qV $ …. (i) K.E. of second particle $ =\frac{1}{2}m_{2}v_{2}^{2}=qV $ After entering the magnetic field, a magnetic force acts on the charged particle which moves the charged particle in circular path of radius $ R=\frac{\sqrt{2mK}}{qB} $ Here, K, q, B are equal
$ \therefore R^{2}\propto m\Rightarrow \frac{m_{1}}{m_{2}}=\frac{R_{1}^{2}}{R_{2}^{2}} $ From (i) and (ii)