Magnetic Effects Of Current Question 412
Question: A charged sphere of mass m and charge - q starts sliding along the surface of a smooth hemispherical bowl, at position P. The region has a transverse uniform magnetic field B. Normal force by the surface of bowl on the sphere at position Q is
Options:
A) $ mg,\sin \theta +qB\sqrt{2g,R,\sin ,\theta } $
B) $ 3,mg,\sin \theta +qB\sqrt{2g,R,\sin ,\theta } $
C) $ mg,\sin \theta -qB\sqrt{2g,R,\sin ,\theta } $
D) $ 3,mg,\sin \theta -qB\sqrt{2g,R,\sin ,\theta } $
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Answer:
Correct Answer: B
Solution:
[b] $ v=\sqrt{2gR,\sin \theta } $ and $ F=qvB $ Now $ N-(F+mg,\sin \theta )=\frac{mv^{2}}{R} $
$ \therefore N=F+mg,\sin ,\theta +\frac{mv^{2}}{R} $ $ =qB\sqrt{2gR,\sin ,\theta }+mg\sin \theta +2mg\sin \theta $
$ \therefore ,N=3mg\sin \theta +qB\sqrt{2gR\sin \theta } $
BETA
