Magnetic Effects Of Current Question 416
Question: A helium nucleus makes a full rotation in a circle of radius 0.8 meter in 2 sec. The value of the magnetic field induction B in tesla at the centre of circle will be
Options:
A) $ 2\times {{10}^{-19}}{\mu_{0}} $
B) $ {{10}^{-19}}/{\mu_{0}} $
C) $ {{10}^{-19}}{\mu_{0}} $
D) $ 2\times {{10}^{-20}}/{\mu_{0}} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ B=\frac{{\mu_{0}}}{4\pi }\frac{2\pi i}{r} $ where $ i=\frac{2e}{t}=\frac{2\times 1.6\times {{10}^{-19}}}{2}=1.6\times {{10}^{-19}},A $
$ \therefore B=\frac{{\mu_{0}}i}{2r}=\frac{{\mu_{0}}\times 1.6\times {{10}^{-19}}}{2\times 0.8}={\mu_{0}}\times {{10}^{-19}}T $
BETA
