Magnetic Effects Of Current Question 42
The magnetic moment of a current carrying loop is $ 2.1\times {{10}^{-25}},amp\times m^{2} $ . The magnetic field at a point on its axis at a distance of $ 1,{\AA} $ is
Options:
A) $ 4.2\times {{10}^{-2}},weber/m^{2} $
B) $ 4.2\times {{10}^{-3}},weber/m^{2} $
C) $ 4.2\times {{10}^{-4}},weber/m^{2} $
D) $ 4.2\times {{10}^{-5}},weber/m^{2} $
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Answer:
Correct Answer: A
Solution:
Field at a point $ x $ from the centre of a current carrying loop on the axis is $ \text{B}=\frac{{\mu_{\text{0}}}}{4\pi }.\frac{2M}{x^{3}}=\frac{{{10}^{-7}}\times 2\times 2.1\t {{10}^{-25}}}{{{({{10}^{-10}})}^{3}}} $ $ $ $ =4.2\times {{10}^{-32}}\times 10^{30}=4.2\times {{10}^{-2}}T$
BETA
