Magnetic Effects Of Current Question 426
Question: In the figure shown a coil of single turn is wound on a sphere of radius R and mass M. The plane of the coil is parallel to the plane and lies in the equatorial plane of the sphere. Current in the coil is i. The value of B if the sphere is in equilibrium is
Options:
A) $ \frac{mg,\cos ,\theta }{\pi iR} $
B) $ \frac{mg,}{\pi iR} $
C) $ \frac{mg,\tan ,\theta }{\pi iR} $
D) $ \frac{mg,\sin ,\theta }{\pi iR} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] For rotational equilibrium of the sphere about point P. $ (mg,\sin ,\theta )R=M(B,\sin ,\theta ) $ or, $ mgR,\sin ,\theta =i\pi R^{2},B\sin ,\theta $ $ B=mg/\pi iR $
BETA
