Magnetic Effects Of Current Question 44
Question: A particle carrying a charge equal to 100 times the charge on an electron is rotating per second in a circular path of radius 0.8 metre. The value of the magnetic field produced at the centre will be $ ({\mu_{0}}= $ permeability for vacuum) [CPMT 1986; KCET 2001; BHU 2001]
Options:
A) $ \frac{{{10}^{-7}}}{{\mu_{0}}} $
B) $ {{10}^{-17}}{\mu_{0}} $
C) $ {{10}^{-6}}{\mu_{0}} $
D) $ {{10}^{-7}}{\mu_{0}} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ i=\frac{q}{t}=100\times e $ $ {B_{\text{centre}}}=\frac{{\mu_{o}}}{4\pi }.\frac{2\pi i}{r}=\frac{{\mu_{o}}}{4\pi }.\frac{2\pi \times 100e}{r} $ $ =\frac{{\mu_{o}}\times 200\times 1.6\times {{10}^{-19}}}{4\times 0.8}={{10}^{-17}}{\mu_{o}} $
BETA
