Magnetic Effects Of Current Question 446
Question: A long straight wire carries a certain current and produces a magnetic field of $ 2\times {{10}^{-4}}\frac{weber}{m^{2}} $ at a perpendicular distance of 5 cm from the wire. An electron situated at 5 cm from the wire moves with a velocity $ 10^{7},m/s $ towards the wire along perpendicular to it. The force experienced by the electron will be (charge on electron $ =1.6\times {{10}^{-19}}N $ )
Options:
A) Zero
B) $ 3.2,N $
C) $ 3.2,\times {{10}^{-16}}N $
D) $ 1.6,\times {{10}^{-16}}N $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] Given: Magnetic field B $ =2\times {{10}^{-4}},weber/m^{2} $ Velocity of electron, $ v=10^{7},m/s $ Lorentz force $ F=qvB,\sin ,\theta $ $ =1.6\times {{10}^{-19}}\times 10^{7}\times 2\times {{10}^{-4}} $ $ ( \because \theta =90^{o} ) $ $ =3.2\times {{10}^{-16}}N $
BETA
