Magnetic Effects Of Current Question 454
Question: A conducting loop is placed in a magnetic field of strength B perpendicular to its plane. Radius of the loop is r, current in the loop is; and linear mass density of the wire of loop is m. Speed of any transverse wave in the loop will be
Options:
A) $ \sqrt{\frac{Bir}{m}} $
B) $ \sqrt{\frac{Bir}{2m}} $
C) $ \sqrt{\frac{2Bir}{m}} $
D) $ 2\sqrt{\frac{Bir}{m}} $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ F,=Bi\ell $ $ 2T,\sin \frac{\theta }{2}=F $ or $ 2T( \frac{\theta }{2} )=Bi(r\theta ) $
$ \therefore T=Bir $ Now speed, $ v=\sqrt{\frac{T}{m}} $ $ =\sqrt{\frac{Bir}{m}} $
BETA
