Magnetic Effects Of Current Question 50
Question: A long solenoid is formed by winding 20 turns/cm. The current necessary to produce a magnetic field of 20 millitesla inside the solenoid will be approximately $ (\frac{{\mu_{0}}}{4\pi }={{10}^{-7}},tesla-metre/ampere) $ [MP PMT 1994]
Options:
A) 8.0 A
B) 4.0 A
C) 2.0 A
D) 1.0 A
Show Answer
Answer:
Correct Answer: A
Solution:
$ B={\mu_{0}}ni\Rightarrow i=\frac{B}{{\mu_{0}}n} $ $ =\frac{20\times {{10}^{-3}}}{4\pi \times {{10}^{-7}}\times 20\times 100} $ = $ 7.9,amp=8amp $
BETA
