Magnetic Effects Of Current Question 57
Question: Due to 10 ampere of current flowing in a circular coil of 10 cm radius, the magnetic field produced at its centre is $ 3.14\times {{10}^{-3}},Weber/m^{2} $ . The number of turns in the coil will be [MP PET 1996]
Options:
A) 5000
B) 100
C) 50
D) 25
Show Answer
Answer:
Correct Answer: C
Solution:
$ B=\frac{{\mu_{0}}}{4\pi }\cdot \frac{2\pi Ni}{r} $
Þ $ 3.14\times {{10}^{-3}}=\frac{{{10}^{-7}}\times 2\times 3.14\times N\times 10}{(10\times {{10}^{-2}})} $
Þ $ N=50 $
BETA
