Magnetic Effects Of Current Question 58
Question: There are 50 turns of a wire in every cm length of a long solenoid. If 4 ampere current is flowing in the solenoid, the approximate value of magnetic field along its axis at an internal point and at one end will be respectively [MP PET 1996]
Options:
A) $ 12.6\times {{10}^{-3}},Weber/m^{2},\ 6.3\times {{10}^{-3}},Weber/m^{2} $
B) $ 12.6\times {{10}^{-3}},Weber/m^{2},\ 25.1\times {{10}^{-3}},Weber/m^{2} $
C) $ 25.1\times {{10}^{-3}},Weber/m^{2},\ 6.3\times {{10}^{-3}},Weber/m^{2} $
D) $ 25.1\times {{10}^{-5}},Weber/m^{2},\ 6.3\times {{10}^{-5}},Weber/m^{2} $
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Answer:
Correct Answer: C
Solution:
The magnetic field in the solenoid along its axis (i) At an internal point $ ={\mu_{o}}ni $ $ =4\pi \times {{10}^{-7}}\times 5000\times 4=25.1\times {{10}^{-3}}Wb/m^{2} $ $ (\text{Here }n=50,turns/cm=5000,turns/m) $ (ii) At one end $ B_{end}=\frac{1}{2}B_{in}=\frac{{\mu_{0}}ni}{2}=\frac{25.1\times {{10}^{-3}}}{2} $ $ =12.6\times {{10}^{-3}}Wb/m^{2} $
BETA
