Magnetic Effects Of Current Question 84
Question: A straight wire carrying a current 10 A is bent into a semicircular arc of radius 5 cm. The magnitude of magnetic field at the center is [CPMT 2000]
Options:
A) $ 1.5\times {{10}^{-5}},T $
B) $ 3.14\times {{10}^{-5}},T $
C) $ 6.28\times {{10}^{-5}},T $
D) $ 19.6\times {{10}^{-5}}T $
Show Answer
Answer:
Correct Answer: C
Solution:
$ B=\frac{{\mu_{0}}}{4\pi }\times \frac{\pi i}{r}\Rightarrow B={{10}^{-7}}\times \frac{\pi \times 10}{5\times {{10}^{-2}}}=6.28\times {{10}^{-5}},T $
BETA
