Magnetism Question 115
Question: The time period of oscillation of a bar magnet suspended horizontally along the magnetic meridian is T0. If this magnet is replaced by another magnet of the same size and pole strength but with double the mass, the new time period will be
[SCRA 1994; JIPMER 2001, 02]
Options:
A) $ \frac{T _{0}}{2} $
B) $ \frac{T _{0}}{\sqrt{2}} $
C) $ \sqrt{2}T _{0} $
D) $ 2T _{0} $
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Answer:
Correct Answer: C
Solution:
$ T=2\pi \sqrt{\frac{I}{MB _{H}}}\Rightarrow T\propto \sqrt{I}\propto \sqrt{\text{w}}\Rightarrow {T}’=\sqrt{2}\ T _{0} $
BETA
