Magnetism Question 271
Question: A current carrying coil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth’s magnetic field be $ H _{0} $ and magnetic field inside the loop be H. If a magnet is suspended inside the loop, it makes angle $ \theta $ with H. Then $ \theta $ =
Options:
A) $ {{\tan }^{-1}}( \frac{H _{0}}{H} ) $
B) $ {{\tan }^{-1}}( \frac{H}{H _{0}} ) $
C) $ \cos e{{c}^{-1}}( \frac{H}{H _{0}} ) $
D) $ {{\cot }^{-1}}( \frac{H _{0}}{H} ) $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ \tan ,\theta =\frac{H _{0}}{H} $
$ \theta ={{\tan }^{-1}}( \frac{H _{0}}{H} ) $
BETA
