Magnetism Question 284
Question: A magnetising field of $ 2\times 10^{3},amp/m $ produces a magnetic flux density of $ 8\pi ,,Tesla $ in an iron rod. The relative permeability of the rod will be -
Options:
A) $ 10^{2} $
B) $ 10^{0} $
C) $ 10^{4} $
D) $ 10^{1} $
Show Answer
Answer:
Correct Answer: C
Solution:
[c] $ \because ,,,{\mu _{r}}=\frac{\mu }{{\mu _{0}}}=\frac{B}{H{\mu _{0}}} $ or $ {\mu _{r}} $
$ =\frac{8\pi }{2\times 10^{3}\times 4\pi \times {{10}^{-7}}}=10^{4} $
BETA
