Magnetism Question 108
Two normal uniform magnetic fields contain a magnetic needle making an angle 60° with H. Then the ratio of $ \frac{F}{H} $ is
[CPMT 1987; DPMT 2001]
Options:
A) 1 : 2
B) 2 : 1
C) $ \sqrt{3}:1 $
D) $ 1:\sqrt{3} $
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Answer:
Correct Answer: D
Solution:
From figure at equilibrium $ \tan 60{}^\circ =\frac{H}{F} $
Therefore $ \sqrt{3}=\frac{F}{H} $
Therefore $ \frac{F}{H}=\frac{1}{\sqrt{3}} $
BETA
