Magnetism Question 294
Question: The mass of a speciment of a ferromagnetic material is 0.6 kg. and its density is $ 7.8\times 10^{3},kg/m^{3} $ . If the area of hysteresis loop of alternating magnetising field of frequency 50Hz is 0.722 MKS units then the hysteresis loss per second will be
Options:
A) $ 277.7\times {{10}^{-5}},joule $
B) $ 277.7\times {{10}^{-6}},joule $
C) $ 277.7\times {{10}^{-4}},joule $
D) $ 27.77\times {{10}^{-4}},joule $
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ W _{H}=VA,ft=\frac{m}{d},,Aft $
$ =\frac{0.6}{7.8\times 10^{3}}\times 0.722\times 50=277.7\times {{10}^{-5}},Joule $
BETA
