Magnetism Question 30
Question: The true value of angle of dip at a place is 60o, the apparent dip in a plane inclined at an angle of 30o with magnetic meridian is
[AIEEE 2002]
Options:
A) $ {{\tan }^{-1}}\frac{1}{2} $
B) $ {{\tan }^{-1}}(2) $
C) $ {{\tan }^{-1}}( \frac{2}{3} ) $
D) None of these
Show Answer
Answer:
Correct Answer: B
Solution:
$ \tan {{\varphi }^{’}}=\frac{\tan \varphi }{\cos \beta }; $ where $ {{\varphi }^{’}} $ =Apparent angle of dip, $ \varphi $ = True angle of dip, $ \beta $ =Angle made by vertical plane with magnetic meridian.
$ \Rightarrow \tan {{\varphi }^{’}}=\frac{\tan 60^{o}}{\cos 30^{o}}=2\Rightarrow {{\varphi }^{’}}={{\tan }^{-1}}( 2 ) $
BETA
