Magnetism Question 198
Question: A magnet when placed perpendicular to a uniform field of strength $ {{10}^{-4}}Wb/m^{2} $ experiences a maximum couple of moment $ 4\times {{10}^{-5}}N/m. $ . What is its magnetic moment
[Bihar MEE 1995]
Options:
A) $ 0.4A\times m^{2} $
B) $ 0.2A\times m^{2} $
C) $ 0.16A\times m^{2} $
D) $ 0.04A\times m^{2} $ (e) $ 0.06A\times m^{2} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ {C _{\max }}=MB\Rightarrow 4\times {{10}^{-5}}=M\times {{10}^{-4}}\Rightarrow M=0.4\ A\times m^{2} $
BETA
