Magnetism Question 35
Question: The dipole moment of each molecule of a paramagnetic gas is $1.5 \times 10^{23} amp/ m^2$. The temperature of gas is $27^o$C and the number of molecules per unit volume in it is $2 \times 10^{26} m^3$. The maximum possible intensity of magnetisation in the gas will be
Options:
A) $3 \times 10^3 amp/m$
B) $4 \times 10^3 amp/m$
C) $5 \times 10^5 amp/m$
D) $ 6 \times 10^4 amp/m$
Show Answer
Answer:
Correct Answer: A
Solution:
$ I=\frac{M}{V}=\frac{\mu N}{V}=\frac{1.5\times {{10}^{-23}}\times 2\times 10^{26}}{1}=3\times 10^{3}Amp/m $
BETA
