Magnetism Question 48
Question: A dip needle lies initially in the magnetic meridian when it shows an angle of dip $\theta$ at a place. The dip circle is rotated through an angle x in the horizontal plane and then it shows an angle of dip $ {\theta }’ $ . Then $ \frac{\tan {\theta }’}{\tan \theta } $ is
Options:
A) $ \frac{1}{\cos x} $
B) $ \frac{1}{\sin x} $
C) $ \frac{1}{\tan x} $
D) $ \cos x $
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Answer:
Correct Answer: A
Solution:
In first case $ \tan \theta =\frac{B _{V}}{B _{H}} $ ….. (i) Second case $ \tan {{\theta }^{’}}=\frac{B _{V}}{B _{H}\cos x} $ ….. (ii) From equation (i) and (ii), $ \frac{\tan \theta ‘}{\tan \theta }=\frac{1}{\cos x} $
BETA
