Magnetism Question 53
Question: At a certain place, the horizontal component of earth’s magnetic field is $ \sqrt{3} $ times the vertical component. The angle of dip at that place is
[MP PMT 1984, 85; AFMC 2000]
Options:
A) $ 60{}^\circ $
B) $ 45{}^\circ $
C) $ 90{}^\circ $
D) $ 30{}^\circ $
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Answer:
Correct Answer: D
Solution:
$ B _{H}=\sqrt{3}\ B _{V}, $ also $ \tan \theta =\frac{B _{V}}{B _{H}}=\frac{1}{\sqrt{3}}\Rightarrow \theta =30^{o} $
BETA
