Magnetism Question 56
Question: If the angles of dip at two places are 30o and 45o respectively, then the ratio of horizontal components of earth’s magnetic field at the two places will be
[MP PET 1989]
Options:
A) $ \sqrt{3}:\sqrt{2} $
B) $ 1:\sqrt{2} $
C) $ 1:\sqrt{3} $
D) $ 1:2 $
Show Answer
Answer:
Correct Answer: A
Solution:
The horizontal components are $ {{(B _{H})} _{1}}=B\cos {\varphi _{1}} $ and
$ (B_H)_2=B\cos \varphi _2 $
$ \
Therefore ,\frac{(B_H)_1}{(B_H)_2}$
=$\frac{\cos {\varphi _{1}}}{\cos {\varphi _{2}}}=\frac{\cos 30^{o}}{\cos 45^{o}}=\frac{\sqrt{3}}{2}\times \sqrt{2}=\frac{\sqrt{3}}{\sqrt{2}} $
BETA
