Magnetism Question 58
Question: The angle of dip at a place is 40.6o and the intensity of the vertical component of the earth’s magnetic field $ V=6\times {{10}^{-5}} $ Tesla. The total intensity of the earth’s magnetic field (I) at this place is
[MP PMT 1993]
Options:
A) $ 7\times {{10}^{-5}}tesla $
B) $ 6\times {{10}^{-5}}tesla $
C) $ 5\times {{10}^{-5}}tesla $
D) $ 9.2\times {{10}^{-5}}tesla $
Show Answer
Answer:
Correct Answer: D
Solution:
From the relation $ B _{V}=I\sin \varphi $
$ I=\frac{V}{\sin \varphi }=\frac{6\times {{10}^{-5}}}{\sin {{40.6}^{o}}}=\frac{6\times {{10}^{-5}}}{0.65}=9.2\times {{10}^{-5}} $ tesla
BETA
