Magnetism Question 75
Question: The horizontal component of the earth’s magnetic field is 0.22 Gauss and total magnetic field is 0.4 Gauss. The angle of dip. is
[MP PMT 2004]
Options:
A) $ {{\tan }^{-1}},(1) $
B) $ {{\tan }^{-1,}}(\infty ) $
C) $ {{\tan }^{-1,}}(1.518) $
D) $ {{\tan }^{-1,}}(\pi ) $
Show Answer
Answer:
Correct Answer: C
Solution:
By using $ B _{H}=B\cos \varphi $
Therefore $ \cos \varphi =\frac{B _{H}}{B}=\frac{0.22}{0.4} $
Therefore $ \tan \varphi =\frac{\sqrt{{{(0.4)}^{2}}-{{(0.22)}^{2}}}}{0.22} $
Therefore $ \varphi ={{\tan }^{-1}}(1.518) $
BETA
