Magnetism Question 122
The time period of a thin bar magnet in earth’s magnetic field is T. If the magnet is cut into two equal parts perpendicular to its length, the time period of each part in the same field will be T/√2
[MP PET 2001]
Options:
A) $ \frac{T}{2} $
T
C) $ \sqrt{2}T $
2T
Show Answer
Answer:
Correct Answer: A
Solution:
$ {T}’=\frac{T}{n} $
BETA
