Magnetism Question 77
Question: A current carrying coil is placed with its axis perpendicular to N-S direction. Let horizontal component of earth’s magnetic field be Ho and magnetic field inside the loop is H. If a magnet is suspended inside the loop, it makes angle $ \theta $ with H. Then $ \theta $ =
[Orissa PMT 2004]
Options:
A) $ {{\tan }^{-1}}( \frac{H _{0}}{H} ) $
B) $ {{\tan }^{-1}}( \frac{H}{H _{0}} ) $
C) $ \cos e{{c}^{-1}}( \frac{H}{H _{0}} ) $
D) $ {{\cot }^{-1}}( \frac{H _{0}}{H} ) $
Show Answer
Answer:
Correct Answer: A
Solution:
In given case H and H0 are perpendicular to each other. From figure $ \tan \theta =\frac{H _{0}}{H} $
Therefore $ \theta ={{\tan }^{-1}}( \frac{H _{0}}{H} ) $
BETA
