Magnetism Question 91
Question: A bar magnet A of magnetic moment MA is found to oscillate at a frequency twice that of magnet B of magnetic moment MB when placed in a vibrating magneto-meter. We may say that
[MP PMT 1991]
Options:
A) $ M _{A}=2M _{B} $
B) $ M _{A}=8M _{B} $
C) $ M _{A}=4M _{B} $
D) $ M _{B}=8M _{A} $
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Answer:
Correct Answer: C
Solution:
$ \nu =\frac{1}{2\pi }\sqrt{\frac{MB _{H}}{I}}\Rightarrow \nu \propto \sqrt{M} $
$ \Rightarrow \frac{{\nu _{A}}}{{\nu _{B}}}=\sqrt{\frac{M _{A}}{M _{B}}}\Rightarrow \frac{2}{1}=\sqrt{\frac{M _{A}}{M _{B}}}\Rightarrow M _{A}=4M _{B} $
BETA
