Magnetism Question 204
Question: A bar magnet of magnetic moment 200 A-m2 is suspended in a magnetic field of intensity 0.25 N/A-m. The couple required to deflect it through 30o is
[AFMC 1999; Pb. PET 2000]
Options:
A) 50 N-m
B) 25 N-m
C) 20 N-m
D) 15 N-m
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Answer:
Correct Answer: B
Solution:
$ \tau =MB\sin \theta $
$ \tau =200\times 0.25\times \sin 30{}^\circ =25\ N\times m. $
BETA
