Magnetism Question 101
Question: The number of turns and radius of cross-section of the coil of a tangent galvanometer are doubled. The reduction factor K will be
[NCERT 1983; MP PMT 2002]
Options:
A) K
B) 2K
C) 4K
D) K/4
Show Answer
Answer:
Correct Answer: A
Solution:
$ K=\frac{2RB _{H}}{{\mu _{0}}N} $ (R = radius, N= number of turns)
BETA
