Magnetism Question 135
Two identical bar magnets are placed one above the other such that they are mutually perpendicular and bisect each other. The time period of this combination in a horizontal magnetic field is T. The time period of each magnet in the same field is
[CPMT 2005]
Options:
A) $ \sqrt{2},T $
B) $ {{2}^{\frac{1}{4}}}T $
C) $ {{2}^{-\frac{1}{4}}}T $
D) $ {{2}^{-\frac{1}{2}}}T $
Show Answer
Answer:
Correct Answer: C
Solution:
Time period of combination $ T=2\pi \sqrt{\frac{2I}{\sqrt{2},M.H}} $ ?..(i) and time period of each magnet $ {T}’=2\pi \sqrt{\frac{I}{MH}} $ ??(ii) from (i) and (ii) we get $ {T}’=\frac{T}{{{2}^{1/4}}}={{2}^{-1/4}}T $
BETA
