Magnetism Question 206
Question: A magnet of magnetic moment $ 50,\hat{i},A\text{-}m^{2} $ is placed along the x-axis in a magnetic field $ \overrightarrow{B}=(0.5,\hat{i}+3.0\hat{j}),T. $ The torque acting on the magnet is
[MP PMT 2000]
Options:
A) 175 $ \hat{k},,N\text{-}m $
B) 150 $ \hat{k},,N\text{-}m $
C) 75 $ \hat{k},,N\text{-}m $
D) $ 25\sqrt{37},\hat{k},,N\text{-}m $
Show Answer
Answer:
Correct Answer: B
Solution:
$ \overrightarrow{\tau }=\overrightarrow{M}\times \overrightarrow{B}\Rightarrow \overrightarrow{\tau }=50\hat{i}\times (0.5\hat{i}+3\hat{j}) $
$ =150( \hat{i}\times \hat{j} )=150\hat{k}N\times m. $
BETA
