Magnetism Question 155
Question: An iron rod of length L and magnetic moment M is bent in the form of a semicircle. Now its magnetic moment will be
[CPMT 1984; MP Board 1986; NCERT 1975; MP PET/PMT 1988; EAMCET (Med.) 1995; Manipal MEE 1995;RPMT 1996; BHU 1995; MP PET 2002]
Options:
A) $ M $
B) $ \frac{2M}{\pi } $
C) $ \frac{M}{\pi } $
D) $ M\pi $
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Answer:
Correct Answer: B
Solution:
On bending a rod it’s pole strength remains unchanged where as its magnetic moment changes. New magnetic moment $ {M}’=m(2R)=m( \frac{2L}{\pi } )=\frac{2M}{\pi } $
BETA
