Magnetism Question 162
Question: The pole strength of a bar magnet is 48 ampere-metre and the distance between its poles is 25 cm. The moment of the couple by which it can be placed at an angle of 30o with the uniform magnetic intensity of flux density 0.15 Newton /ampere-metre will be
Options:
A) 12 Newton × metre
B) 18 Newton × metre
C) 0.9 Newton × metre
D) None of the above
Show Answer
Answer:
Correct Answer: C
Solution:
$ \tau =MB\sin \theta =48\times 25\times {{10}^{-2}}\times 0.15\times \frac{1}{2} $
$ =0.9\ N\times m $
BETA
