Magnetism Question 208
Question: A bar magnet of magnetic moment 3.0 A-m2 is placed in a uniform magnetic induction field of 2 ´ $10^5$ T. If each pole of the magnet experiences a force of 6 ´ $10^4$ N, the length of the magnet is
[EAMCET (Med.) 2000]
Options:
A) 0.5 m
B) 0.3 m
C) 0.2 m
D) 0.1 m
Show Answer
Answer:
Correct Answer: D
Solution:
$ F=mB\Rightarrow F=\frac{M}{L}\times B $
$ \Rightarrow 6\times {{10}^{-4}}=\frac{3}{L}\times 2\times {{10}^{-5}}\Rightarrow L=0.1\ m. $
BETA
