Magnetism Question 169
The figure below shows the north and south poles of a permanent magnet in which n turn coil of area of cross-section A is resting, such that for a current i passed through the coil, the plane of the coil makes an angle $ \theta $ with respect to the direction of magnetic field B. If the plane of the coil and the magnetic field are horizontal and vertical respectively, the torque on the coil will be
[CPMT 1986, 88; DPMT 2002]
Options:
A) $ \tau =niAB\cos \theta $
B) $ \tau =niAB\sin \theta $
C) $ \tau =niAB $
D) None of the above, since the magnetic field is radial
Show Answer
Answer:
Correct Answer: A
Solution:
Plane of coil makes an angle $ \theta $ with the magnetic field. $ \
Therefore \ \tau =MB\sin (90-\theta ) $ or $ \tau =niAB\sin \theta $ [As M =niA]
BETA
