Magnetism Question 183
Question: Force between two unit pole strength placed at a distance of one metre is
[CPMT 1987]
Options:
A) 1 N
B) $ \frac{{{10}^{-7}}}{4\pi }N $
C) $ {{10}^{-7,}},N $
D) $ 4\pi \times {{10}^{-7}}N $
Show Answer
Answer:
Correct Answer: C
Solution:
$ F={{10}^{-7}}\times \frac{m^{2}}{r^{2}}=\frac{{{10}^{-7}}{{( 1 )}^{2}}}{{{( 1 )}^{2}}}={{10}^{-7}}N $
BETA
