Magnetism Question 186
Question: Rate of change of torque $ \tau $ with deflection $ \theta $ is maximum for a magnet suspended freely in a uniform magnetic field of induction B, when
[MP PET 1994]
Options:
A) $ \theta =0{}^\circ $
B) $ \theta =45{}^\circ $
C) $ \theta =60{}^\circ $
D) $ \theta =90{}^\circ $
Show Answer
Answer:
Correct Answer: A
Solution:
$ \tau =MB _{H}\sin \theta $ or $ \frac{d\tau }{d\theta }=MB _{H}\cos \theta $ This will be maximum. when $ \theta ={{0}^{o.}} $
BETA
