Magnetism Question 187
Question: A magnet of magnetic moment M is rotated through 360° in a magnetic field H, the work done will be
[KCET 1998; MP PMT 1994; Roorkee 2000]
Options:
A) MH
B) 2MH
C) $ 2\pi MH $
D) Zero
Show Answer
Answer:
Correct Answer: D
Solution:
$ W=MB( \cos {\theta _{1}}-\cos {\theta _{2}} );\ \ {\theta _{1}}=0^{o}\text{and}\ {\theta _{2}}=360^{o} $
$ \Rightarrow W=0 $
BETA
